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MasteringChemistry with Pearson eText Student Access Code Card for Chemistry (6th) Edition 0321723430 9780321723437

MasteringChemistry with Pearson eText Student Access Code Card for Chemistry (6th Edition) Edit edition This problem has been solved: Solutions for Chapter 2 …

Law of multiple proportions states that elements can combine in different ways to form different substances, whose mass ratios are small whole-number multiplies of each other.

pearson chapter 2 homework

We have substance A formed from combination of 6.00 g sulfur and 5.99 g oxygen.

So the mass ratio of sulfur to oxygen in A is

pearson chapter 2 homework

We have substance B formed from combination of 8.60 g sulfur and 12.88 g oxygen.

So the mass ratio of sulfur to oxygen in B is

pearson chapter 2 homework

Now, compare the mass ratio of sulfur to oxygen in A and B:

pearson chapter 2 homework

Thus, twice the mass ratio of S, O in A is equal to thrice the mass ratio in B.

Corresponding textbook

MasteringChemistry with Pearson eText Student Access Code Card for Chemistry | 6th Edition

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