Part A: Standardization of NaOH | | | | |
| | | | |
| Trial 1 | Trial 2 | Trial 3 | units |
Volume HCl pipetted into flask: | 25 | 25 | 25 | mL |
Molarity HCl pipetted: | 0.11 | 0.11 | 0.11 | M |
Volume reading, initial (NaOH): | 0 | 0 | 0 | mL |
Volume reading, final (NaOH): | 25.78 | 26.19 | 26.18 | mL |
Volume of NaOH let out of buret: | 25.78 | 26.19 | 26.18 | mL |
Molarity NaOH: | 0.107 | 0.105 | 0.105 | M |
| Average M of NaOH: | 0.106 | M |
| Average Dev. Of M NaOH: | 0.001 | M |
| | | | |
Part B: Antacid Tablet Analysis | | | | |
| Trial 1 | Trial 2 | Trial 3 | units |
Vol. HCl added to flask total: | 25 | 25 | 25 | mL |
M HCl: | 0.524 | 0.524 | 0.524 | M |
Volume reading, initial (NaOH): | 0 | 0 | 0 | mL |
Volume reading, final (NaOH): | 17.08 | 15.8 | 16.38 | mL |
Volume of NaOH let out of buret: | 17.08 | 15.8 | 16.38 | mL |
M NaOH: | 0.106 | 0.106 | 0.106 | M |
Total moles HCl added to tablet: | 0.0131 | 0.0131 | 0.0131 | mol |
Moles NaOH added from buret: | 0.00181 | 0.00167 | 0.00174 | mol |
Moles HCl neutralized by tablet: | 0.0113 | 0.0114 | 0.0114 | mol |
Moles of active ingredient: | 0.0226 | 0.0229 | 0.0227 | mol |
Mass of active ingredient: | 565 | 572 | 569 | mg |
| | | | |
| Avg mass of active ingredient: | 568 mg |
| Average deviation in mass: | 2 mg |
| Percent Error | | 14% |
From Part A of this experiment, it was found that the average volume of titrant used to complete the reaction was approximately 26.05 mL meaning that it took about 26 mL of NaOH (aq) for the moles of each reagent to equal each other. This makes sense considering that both are stoichiometrically equivalent given their common molar coefficient. Therefore they both reagents should require similar volumes to reach equilibrium. Given this volume, the molarity of NaOH (aq) was calculated to be an average of 0.106 M ± 0.001. When this standardized titrant was used in Part B of the experiment, its average volume of 16.42 mL determined the amount of HCl (aq) left unreacted from the buffer reaction with CaCO 3(aq) to be an average of 0.00174 moles. The amount of HCl (aq) neutralized by the reaction was then used to calculate the moles of CaCO 3(aq) in the tablet. Then it was converted to a theoretical mass of 568mg in comparison to the actual mass of 500mg. This value is within reason due to the antacid brand’s unusually high range of uncertainty of ± 50 mg making the error a mere 14%. A few observable results of this reaction would include the significant color changes indicating the midrange and endpoint of the reaction. The solution would produce a vibrant purple when the indicator was added and it would abruptly shift from purple to grey and soon after, from grey to green. Another observation would be the chemical reaction between the antacid and the HCl (aq) . The solution produced heat, gas, and condensation along the sides of the Erlenmeyer flask as a result of the CO 2(g) and H 2 O (g) escaping the system.
Discussion:
Throughout this experiment, several environmental influences played a big role on the measured data as well as precision. A major source or error occurred in the measurement of CaCO 3(s) in the antacid tablet. The active ingredient of a tums tablet was measured in 1 significant figure and measured under an increment of hundreds. Therefore, the uncertainty of the company measurement was ± half of each hundred, which is far too great of a range to truly have an accurate read on how effective the experiment was. Another issue arose with the crushed antacid tablet. After crushing the Tums tablet thoroughly with the mortar and pestle, when the powder was transferred to the solution, it was difficult to completely dissociate in the solution. Even after constant stirring and swirling, a few small regions of powder settled to the bottom and formed small clumps. While heating, this could have prevented a 100% complete reaction between HCl (aq) and the antacid despite the excessive heat. It may have left more excess HCl than would normally have been. The final source of error could have been due to the composition of the antacid tablet itself. In this experiment, only the Calcium Carbonate was considered in the chemical formula however there may have been other ingredients within the tablet that could influence the concentration of substances of the reaction. Within an uncertain concentration of CaCO 3(s) , there is an amount of uncertainty in the measured data.
Formula Copy
![titration experiment of hcl and naoh Formula-Copy](https://www.odinity.com/wp-content/uploads/2013/11/Formula-Copy.png)
Works Cited
Murphy, K. (2012). Acid-Base Titrations. A Labratory Manual for General Chemistry (5th ed., pp. 305-311).
Amherst, New York: Daemen College
Swartz, D. (Director) (2013, April 3). Experiment 19A: Standardize NaOH. Chemistry II
Lab. Lecture conducted from Daemen College, Amherst.
Swartz, D. (Director) (2013, April 10). Experiment 19B: Back Titration. Chemistry II
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a student performed a titration using 12.5. ml of naoh solution with 0.5 m hcl solution. if 50.0 ml of hcl was consumed during the titration, calculate the concentration of naoh.
if 50.0 ml of hcl was consumed during the titration concentration of naoh is [tex]$0.25 \mathrm{M}$[/tex]
Explanation:
[tex]0.500 \frac{\mathrm{mol}}{\mathrm{L}} \mathrm{H}_2 \mathrm{SO}_4 \cdot 0.0125 \mathrm{~L}=0.00625 \mathrm{molH}_2 \mathrm{SO}_4[/tex]
Write a balanced equation for the reaction:
[tex]$$\begin{aligned}& \mathrm{H}_2 \mathrm{SO}_4+2 \mathrm{NaOH} \rightarrow 2 \mathrm{H}_2 \mathrm{O}+\mathrm{Na}_2 \mathrm{SO}_4 \\& 1 \text { mol } \mathrm{H}_2 \mathrm{SO} 4 \text { neutralizes } 2 \mathrm{~mol} \mathrm{NaOH} \text {, so: } \\& 0.00625 \cdot 2=0.0125 \mathrm{~mol} \mathrm{NaOH} \\& 0.0125 \mathrm{~mol} \mathrm{NaO} \frac{\mathrm{H}}{0.05} L=0.25 \mathrm{MNaOH}\end{aligned}$$[/tex]
concentration of naoh is 0.25 M
In chemistry, concentration is the abundance of a constituent divided by the total volume of a mixture. Several types of mathematical description can be distinguished: mass concentration, molar concentration, number concentration, and volume concentration.
You can determine how much solute has been dissolved in the solvent by looking at the concentration of the solution. For instance, the concentration could be stated as 1 teaspoon of salt per 2 cups of water if you add 1 teaspoon to 2 cups of water.
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Enhanced adsorption of aqueous pb(ii) by acidic group-modified biochar derived from peanut shells.
![ORCID titration experiment of hcl and naoh](https://pub.mdpi-res.com/img/design/orcid.png?0465bc3812adeb52?1719920548)
1. Introduction
2. materials and methods, 2.1. materials, 2.2. ambc preparation, 2.3. acid–base titration, 2.4. characterization, 2.5. adsorption test, 3. results and discussion, 3.1. characterization of adsorbents, 3.2. pb(ii) adsorption by ambc, 3.2.1. effects of contact time, 3.2.2. effects of ph value, 3.2.3. effects of the dosage of ambc, 3.2.4. effects of initial pb(ii) concentration, 3.3. comparison of pre-ambc and ambc with other adsorbents, 3.4. pb(ii) adsorption isotherms, 3.5. thermodynamic study of the adsorption, 3.6. kinetics study of the adsorption, 3.7. possible adsorption mechanisms, 4. conclusions, author contributions, data availability statement, acknowledgments, conflicts of interest.
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Click here to enlarge figure
Adsorbent | S (m /g) | V (cm /g) | D (nm) | Acid Density (mmol/g) |
---|
Total | Ph-OH | -SO H | -COOH |
---|
Pre-AMBC | 832.6 | 3.99 × 10 | 2.2 | 1.26 | 0.05 | - | 1.21 |
AMBC | 329.3 | 2.67 × 10 | 2.1 | 2.28 | 0.33 | 0.52 | 1.43 |
Adsorbents | Q (mg/g) | R (%) |
---|
Pre-AMBC | 83.1 | 39.7 |
AMBC | 148.6 | 76.0 |
Adsorbents | Q (mg/g) | Activator | Experiment Conditions |
---|
pH | T (°C) | Dosage (g/L) | Equilibration Time (min) | Initial Concentration (mg/g) | Ref. |
---|
AMBC | 148.6 | H SO | 5 | 25 | 0.5 | 120 | 100 | This study |
C-KOH | 57.5 | KOH | 5 | 25 | 2 | 35 | 100 | [ ] |
SBC | 191.1 | H SO | 4.5 | - | 2 | 5 | 200 | [ ] |
HP-BC | 60.9 | H O | 5 | 25 | - | 500 | 100 | [ ] |
M-RH-AC | 134.9 | HNO | 5.5 | - | 1 | 90 | 180 | [ ] |
PLAC | 98.4 | H PO | 5.0 | 25 | 0.6 | 30 | 80 | [ ] |
Temperature (°C) | Langmuir Model | Freundlich Model |
---|
K (L/mg) | q (mg/g) | R | R | K (mg/g) | 1/n | R |
---|
25 | 0.0716 | 210.1 | 0.046~0.195 | 0.98947 | 68.117 | 0.211 | 0.97800 |
35 | 0.0786 | 220.3 | 0.048~0.203 | 0.98606 | 69.611 | 0.215 | 0.98978 |
45 | 0.0826 | 318.5 | 0.053~0.218 | 0.96706 | 75.708 | 0.280 | 0.97686 |
Temperature (°C) | K | ΔG (kJ/mol) | ΔH (kJ/mol) | ΔS (kJ/mol.K) |
---|
25 | 5.304 | −4.14 | 3.248 | 0.025 |
35 | 5.334 | −4.29 |
45 | 4.764 | −4.13 |
Temperature °C | q mg/g | k g/(min.mg) | R |
---|
25 | 147.0 | 5.53 × 10 | 0.99989 |
35 | 155.3 | 6.92 × 10 | 0.99991 |
55 | 157.5 | 8.71 × 10 | 0.99992 |
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Wu, Y.; Li, C.; Wang, Z.; Li, F.; Li, J.; Xue, W.; Zhao, X. Enhanced Adsorption of Aqueous Pb(II) by Acidic Group-Modified Biochar Derived from Peanut Shells. Water 2024 , 16 , 1871. https://doi.org/10.3390/w16131871
Wu Y, Li C, Wang Z, Li F, Li J, Xue W, Zhao X. Enhanced Adsorption of Aqueous Pb(II) by Acidic Group-Modified Biochar Derived from Peanut Shells. Water . 2024; 16(13):1871. https://doi.org/10.3390/w16131871
Wu, Yumeng, Ci Li, Zhimiao Wang, Fang Li, Jing Li, Wei Xue, and Xinqiang Zhao. 2024. "Enhanced Adsorption of Aqueous Pb(II) by Acidic Group-Modified Biochar Derived from Peanut Shells" Water 16, no. 13: 1871. https://doi.org/10.3390/w16131871
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Stage 1. Using a small funnel, pour a few cubic centimetres of 0.4 M hydrochloric acid into the burette, with the tap open and a beaker under the open tap. Once the tip of the burette is full of solution, close the tap and add more solution up to the zero mark. (Do not reuse the acid in the beaker - this should be rinsed down the sink.)
This leaves the final product to simply be water, this is displayed in the following example involving hydrochloric acid (HCl) and sodium hydroxide (NaOH). From Table \(\PageIndex{1}\), you can see that HCl is a strong acid and NaOH is a strong base. Therefore, the reaction between HCl and NaOH is initially written out as follows:
Titrate with NaOH solution till the first color change. result calculation. According to the reaction equation. HCl + NaOH → NaCl + H 2 O. Hydrochloric acid reacts with sodium hydroxide on the 1:1 basis. That makes calculation especially easy - when we calculate number of moles of NaOH used it will be already number of moles of HCl titrated.
Titration Experiment. In the neutralization of hydrochloric acid by sodium hydroxide, the mole ratio of acid to base is 1:1. HCl(aq) + NaOH(aq) → NaCl(aq) +H2O(l) (7.18.1) (7.18.1) HCl ( a q) + NaOH ( a q) → NaCl ( a q) + H 2 O ( l) One mole of HCl HCl would be fully neutralized by one mole of NaOH NaOH. If instead the hydrochloric acid was ...
Add about 6 mL (use a 10-mL graduated cylinder) of the 50% sodium hydroxide solution to a 1-liter bottle. Fill the bottle to its shoulder with the distilled water. Place the stopper or the lid on the bottle, and thoroughly mix the solution by shaking the bottle. Warning: Concentrated NaOH is very corrosive!
A titration is an experiment where a volume of a solution of known concentration is added to a volume of another solution in order to determine its concentration. Many titrations are acid-base neutralization reactions, though other types of titrations can also be performed. In order to perform an acid-base titration, the chemist must have a way ...
A titration is an analytical procedure used to determine the accurate concentration of a sample by reacting it with a standard solution. One type of titration uses a neutralization reaction, in which an acid and a base react to produce a salt and water: In equation 1, the acid is HCl (hydrochloric acid) and the base is NaOH (sodium hydroxide).
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Lab Report #4. um HydroxideSCH3U. 02Thursday, December 19, 2013Introd. tion The following lab was an acid-base neutralizing titration. A titration is a technique, in which a reagent, called a titrant, of known concentration is use. to determine the concentration of an analyte or unknown solution. Using a.
When the end-point of the titration is reached, the color of the solution changes from colorless to pink. Procedures. You will use the Determine the concentration of an unknown HCl solution and Standardization of NaOH experiment (OLI Unit 3 - Module 11)
Must see: My new website at http://ww.acechemistry.co.uk. This video, with the help of flash animations, shows and explains how you can determine the concent...
A titration is a process used to determine the volume of a solution needed to react with a given amount of another substance. In this experiment, you will titrate hydrochloric acid solution, HCl, with a basic sodium hydroxide solution, NaOH. The concentration of the NaOH solution is given and you will determine the unknown concentration of the HCl. Hydrogen ions from the HCl react with ...
In this thermometric titration, students can determine the end-point of the titration using the highest temperature recorded during the experiment. Using a pipette and safety filler, transfer 20 cm 3 (or 25 cm 3) of the sodium hydroxide solution into the cup, and measure the steady temperature. Using the burette, add a small portion (3-5 cm 3 ...
Learn how titrations are used to figure out the unknown molarity of solutions.Student Work- https://docs.google.com/document/d/17TFZjASP--7vJKUVoyT-1ySilzzRx...
Figure 1 is a titration curve for the titration of HCl by NaOH, a strong acid and strong base, where 25.0 mL of 0.1 M HCl is titrated with 0.1 M NaOH. NaOH titration of HCl 0 2 4 6 8 10 12 14 0 102030 mL NaOH added p H 40 Phenolphthalein Equivalence Point Methyl Red Figure 1. Titration of 25.0 mL of 0.1M HCl by 0.1 M NaOH. Blocked areas on the ...
Experiment 7 Titration Curves of Strong and Weak Acids and Bases Goals To calibrate a pH probe. To become familiar with acid-base titration curves. To determine the concentration of an unknown acid. Equipment and Materials 0.10 M ammonium hydroxide solution, 0.10 M sodium hydroxide solution, 0.0074 M hydrochloric acid
HCl + NaOH NaCl + H 2 O During the course of the titration, the titrant (NaOH) is added slowly to the unknown solution. As it is added, the HCl is slowly reacted away. The point at which exactly enough titrant (NaOH) has been added to react with all of the analyte (HCl) is called the equivalence point.
About the lab tiration titration lab report aim to find the concentration of sodium hydroxide titrating hydrochloric acid with sodium hydroxide. introduction. ... HCl+NaOH → H2O+NaCl. Predictions. When this experiment is carried out the base in the conical flask should turn colorless after adding acid to the solution. The base solution should ...
In this experiment, the reagents combined are an acid, HCl (aq) and a base, NaOH (aq) where the acid is the analyte and the base is the titrant. The reaction between the two is as follows: HCl (aq) + NaOH (aq) → H2O (l) + Cl -(aq) + Na +(aq) In this case, Sodium and Chloride act as spectator ions and form into salts in a neutralization ...
minus the number of moles that were neutralized by the NaOH: moles acid neutralized = (moles of HCl added) - (moles of NaOH required for back-titration) = (MHCl x VHCl) - (MNaOH x VNaOH) Eq. 4 where M = molarity and V = volume in liters. In today's experiment, half of the students in the class will analyze Tums tablets
In this video, I have demonstrated the whole experiment related to NaOH vs HCl titration. Also included precautions, practical copy record and important poin...
pH Titrations. In a pH titration you measure the pH as a function of the volume of titrant added and determine the equivalence point as the point in where there is an inflection in the slope of the curve. Figure 7.2.2 7.2. 2 shows the four common types of titrations. Initially the pH is that of the pure analyte.
Procedure Part I: Practicing the Titration Technique - Titration of an Acid of Known Concentration 1. In this portion of the experiment, you will practice titrating 25.00 mL of 0.3000 M HCl (your analyte) with 0.3000 M NaOH (your titrant). You will use your data to calculate the experimental concentration of HCl, with the goal to get as close to 0.3000 M as possible (since we know this is ...
Exercise 1: Titration of HCl solutions In this exercise, we will use two HCl solutions that have been premixed with phenol red, 0.02 M HCl + phenol red and 0.04 M HCl + phenol red, to practice the titration procedure. Watch this Introduction to Exercise 1 video to view the experimental set-up that includes steps 1 and 2 in the protocol below.
One pair performs a careful colorimetric titration of HCL with NaOH and the other pair performs a potentiometric titration of HCL with NaOH. Hence correct sequence is e, a, b, ... To determine the concentration of a sodium thiosulfate solution as in this experiment, a student pipetted 25.0 mL of 0.0100 M potassium iodate (KIO3) solution into a ...
7 is the pH of a solution that results from mixing equal volumes of 0.04M ammonia and a 0.02mM solution of hydrochloric acid.. The pH of a solution that results from mixing equal volumes of 0.04 M ammonia and a 0.02 M solution of hydrochloric acid can be calculated using the formula for the pH of a mixture of weak acids and bases.. The pH of a mixture of weak acids and bases can be calculated ...
Titration is a technique in which an unknown concentration of a solution (the analyte) will be investigated while reacting with a known concentration of another solution (the titrant) until it completely reacts and reaches the equivalence point. In this lab, colorimetric titration is being utilized which the equivalence point is measured by the color change.
Titration involving Sodium Hydroxide and Hydrochloric Acid
Subsequently, HCl solution (50 mL, ... V is the volume of NaOH standard solution used in the titration process, mL; 25 is the volume of NaOH standard solution used, mL; c 0 is the ... concentration (50-200 mg/L) on the adsorption performance were investigated. After the adsorption experiment, the solution was filtered, and the concentration ...